An escape room slot costs the same to run whether two people book it or eight. A minimum party size protects that slot: charge the greater of the actual players or the minimum, times the per-player price.
A couple of 2 against a 4-player minimum at $32 still pays for 4 — $128.
The example
Three bookings, each with the actual players, the room's minimum, and the per-player price.
| A | B | C | D | E | |
|---|---|---|---|---|---|
| 1 | Booking | Players | Min | Price | Revenue |
| 2 | Couple | 2 | 4 | 32 | 128 |
| 3 | Family | 5 | 4 | 32 | 160 |
| 4 | Team | 8 | 4 | 30 | 240 |
The formula
MAX picks the billable head count; the price turns it into revenue:
How it works
Two pieces:
MAX(B2,C2)returns the actual players when the party is big enough, or the minimum when it is not.*D2multiplies that billable count by the per-player price.- Small parties pay the minimum; parties at or above it pay for exactly who shows up.
- Keep the minimum in its own cell — peak weekend slots often carry a higher minimum than weekday ones.
Cap the room at capacity too: wrap the players in MIN against the room's max so an over-booked party does not overcharge.
Try it: interactive demo
Enter the actual players, the room minimum, and the per-player price.
Variations
Cap at room capacity
Bill no more than the room holds, even if the party is huge.
Flat private-room price
Compare per-player revenue to a flat buyout and charge the higher.
Pitfalls & errors
Do not just multiply players by price — a party of two would pay for two and you would lose money on the slot. The MAX against the minimum is what protects the booking.
Advertise the minimum clearly. Customers accept “4-player minimum” far better than a surprise on the invoice, and the formula bills it consistently either way.
Practice workbook
Frequently asked questions
Why use a minimum at all?
How do I stop over-booking a room?
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